HexaDecimal to Binary Conversation is very Easy ! All you need is to keep in mind the following table:
Decimal
|
HexaDecimal
|
Binary
|
0
|
0
|
0000
|
1
|
1
|
0001
|
2
|
2
|
0010
|
3
|
3
|
0011
|
4
|
4
|
0100
|
5
|
5
|
0101
|
6
|
6
|
0110
|
7
|
7
|
0111
|
8
|
8
|
1000
|
9
|
9
|
1001
|
10
|
A
|
1010
|
11
|
B
|
1011
|
12
|
C
|
1100
|
13
|
D
|
1101
|
14
|
E
|
1110
|
15
|
F
|
1111
|
(A62)16 = (101001100010)2 Here is a C Program on how to convert HexaDecimal Numbers into Binary Number:
#include <stdio.h> #include <string.h> int main() { char hex[1000]; int i, j; printf("Enter a HexaDecimal Number: "); scanf("%s",hex); j = strlen(hex); printf("Equivalent Binary Number is: "); for(i=0;i<j;i++){ switch(hex[i]){ case '0': printf("0000"); break; case '1': printf("0001"); break; case '2': printf("0010"); break; case '3': printf("0011"); break; case '4': printf("0100"); break; case '5': printf("0101"); break; case '6': printf("0110"); break; case '7': printf("0111"); break; case '8': printf("1000"); break; case '9': printf("1001"); break; case 'A': printf("1010"); break; case 'B': printf("1011"); break; case 'C': printf("1100"); break; case 'D': printf("1101"); break; case 'E': printf("1110"); break; case 'F': printf("1111"); break; case 'a': printf("1010"); break; case 'b': printf("1011"); break; case 'c': printf("1100"); break; case 'd': printf("1101"); break; case 'e': printf("1110"); break; case 'f': printf("1111"); break; } } }
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